QL-2P4: Orthocentric Pedal Quadrangle Centers


Orthocentric Pedal Quadrangles
For a quadrigon the pedal quadrangle of the Isogonal Center QA-P4 is a parallelogram; for a quadrilateral the pedal quadrangle of the Miquel Point QL-P1 degenerates collinear on QL-L3. Here for a quadrilateral two points are described, whose pedal quadrangle are orthocentric. These points – without their property – are already mentioned by Clawson. See Ref-22, page 248 (38).
Note: a Quadrangle is Orthocentric when the Orthocenter of each Component Triangle coincide with the 4th point of the Quadrangle.
Clawson describes two points X, Y on the “circumcentric circle” (Miquel Circle QL-Ci3) as common intersections of circles through Si,j and Sk,l, orthogonal to the circumcircle through the Miquel Point QL-P1 and Si,j and Sk,l (Si,j intersection of Li and Lj). These points are QL-2P4a and QL-2P4b and have orthocentric pedal quadrangles.
See also Ref-34, EQF-messages #429, #430, #431.
QL-2P4-OrthocentricPedalQuadrangleCenters-02
 
Coordinates:
The coordinates of QL-2P4a/b are very complicated and therefore not mentioned here.
However the coefficients of the line through QL-2P4a/b are relatively simple.
1st CT-coefficient QL-2P4a.QL-2P4b:
b2 c2 l (m - n) (-2 a2 l + a2 m + b2 m - c2 m + a2 n - b2 n + c2 n) *
(-a2 b2 l + b4 l - a2 c2 l - 2 b2 c2 l + c4 l + a2 b2 m - b4 m + b2 c2 m + a2 c2 n + b2 c2 n - c4 n)

Properties:
  • QL-2P4a/b are the Clawson-Schmidt Conjugates (QL-Tf1) of QL-2P1a/b.
  • QL-2P4a.QL-2P4b is the Perpendicular Bisector of QL-P1.CSC(QL-P5), where CSC = Clawson-Schmidt Conjugate QL-Tf1.
  • QL-2P4a and QL-2P4b are collinear with CSCe(QL-L1) and CSCe(QL-P3.QL-P4), where CSCe (Line) = QL-Tf3 = Center of the Clawson Schmidt Conjugate of "Line" (since the Clawson Schmidt Conjugate of a Line is a Circle, there is a center).
    Here CSCe(QL-P3.QL-P4) is a point on the Steiner Line QL-L2
    and CSCe(Newton Line) is the Reflection of QL-P1 in
    QL-2P4a.QL-2P4b.
  • The midpoint of QL-2P4a and QL-2P4b lies on the line CSC(QL-P5).CSC(QL-P7).
  • Let L be a parallel to QL-P3.QL-P4 through QL-P1, let L' be the reflection of L in the 1st Steiner Axis, then the QL-Line Isoconjugate QL-Tf2 of L' is QL-2P4a.QL-2P4b. See [34], EQF-message #431.

 

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