5G-s-P8 4th 5G-Hung’s Point


Let A1A2A3A4A5 be a Pentagon.
Taking subscripts modulo 5, we denote, for i = 1, 2, . . . , 5:
• Li = Line(Ai-1, Ai+1).
• Ci = Circle(Ai-1, Ai+1, Li-2^Li+2) with center Pi. (black circles in picture)
• Si = 2nd intersection point of circles Ci-1^Ci+1.
• Di = Circle(Si, Li+1^Li+2, Li-1^Li-2) with center Qi. (blue circles in picture)
Then lines Pi.Qi will be concurrent in 5G-s-P8 for i = 1, ... , 5.
This point was found by Tran Quang Hung. See Ref-66, QPG-messages #631 and #634.
 
5G s P8 4th 5G Hung's Point 05